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29 September, 05:51

What are the mole fraction and the mass percent of a solution made by dissolving 0.21 g KBr in 0.355 L water? (d = 1.00 g/mL.) mole fraction

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  1. 29 September, 05:52
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    Mol fraction H2O = 0.99991

    Mol fraction KBr = 0.00009

    mass % KBr = 0.059 %

    mass % H2O = 99.941 %

    Explanation:

    Step 1: Data given

    Mass of KBr = 0.21 grams

    Molar mass KBr = 119 g/mol

    Volume of water = 355 mL

    Density of water = 1.00 g/mL

    Molar mass water = 18.02 g/mol

    Step 2: Calculate mass water

    Mass water = 355 mL * 1g / mL

    Mass water = 355 grams

    Step 3: Calculate moles water

    Moles water = mass water / molar mass water

    Moles water = 355 grams / 18.02 g/mol

    Moles water = 19.7 moles

    Step 4: Calculate moles KBr

    Moles KBr = 0.21 grams / 119 g/mol

    Moles KBr = 0.00176 moles

    Step 5: Calculate total moles

    Total moles = 19.7 moles + 0.00176 moles

    Total moles = 19.70176 moles

    Step 6: Calculate mol fraction

    Mol fraction H2O = 19.7 moles / 19.70176 moles

    Mol fraction H2O = 0.99991

    Step 7: Calculate mol fraction KBr

    Mol fraction KBr = 0.00176 / 19.70176

    Mol fraction KBr = 0.00009

    Step 6: Calculate mass %

    mass % KBR = (0.21 grams / (0.21 + 355) grams) * 100%

    mass % KBr = 0.059 %

    mass % H2O = (355 grams / 355.21 grams) * 100%

    mass % H2O = 99.941 %
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