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30 November, 18:08

Select the set of quantum numbers that represents each electron in a ground‑state Be atom. n = 2,? = 0, m? = 0, m s = - 1 2 n = 1,? = 0, m? = 0, m s = + 1 2 n = 2,? = 0, m? = 0, m s = + 1 2 n = 2,? = 1, m? = 0, m s = - 1 2 n = 1,? = 0, m? = - 1, m s = + 1 2 n = 1,? = 0, m? = 0, m s = - 1 2 n = 2,? = 0, m? = 0, m s = - 1 n = 2,? = 1, m? = 1, m s = + 1 2

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  1. 30 November, 18:22
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    n: 1, ℓ: 0, ml: 0, ms:+1/2

    n: 1, ℓ: 0, ml: 0, ms:-1/2

    n: 2, ℓ: 0, ml: 0, ms:+1/2

    n: 2, ℓ: 0, ml: 0, ms:-1/2

    Explanation:

    Beryllium has 4 electrons and its electron configuration is 1s² 2s².

    The principal quantum number (n) describes the level of energy. Then, the first two electrons have n = 1, and the second 2 electrons have n = 2.

    The azimuthal number (ℓ) describes the subshell of energy. All the 4 electrons are in s subshells, which correspond to ℓ = 0.

    The magnetic quantum number (ml) describes the orbital of the subshell. The s subshell has only 1 s orbital, so the only possible value for ml is 0.

    The spin quantum number (ms) describes the spin of the electron and can take 2 values: + 1/2 or - 1/2.

    Considering these rules, the quantum numbers for these 4 electrons are:

    n: 1, ℓ: 0, ml: 0, ms:+1/2

    n: 1, ℓ: 0, ml: 0, ms:-1/2

    n: 2, ℓ: 0, ml: 0, ms:+1/2

    n: 2, ℓ: 0, ml: 0, ms:-1/2
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