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28 March, 13:51

How many grams of Na3AsO3 is produced from the reaction of 6.90 moles of NaOH?

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  1. 28 March, 14:17
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    6.90 mol x grams

    2As + 6NaOH = 2Na3AsO3 + 3H2

    6 mol 2 mol

    192 g/mol

    6.90 mol NaOH x 2 mol Na3AsO3/6 mol NaOH= = 2.3 mol Na3AsO3

    2.3 mol Na3AsO3 x 192 g/mol = 442 g Na3AsO3
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