Calculate the volume in liters of a * 4.3910-5/moll mercury (ii) iodide solution that contains 500. mg of mercury (ii) iodide hgi2. round your answer to 3 significant digits.

The molarity of the solution is 4.39 x 10⁻⁵ mol/L

molarity is the number of moles of solute in 1 L of solution

in this instance there are 4.39 x 10⁻⁵ mol of HgI₂ in 1 L solution

the mass of HgI₂ in 1 L - 4.39 x 10⁻⁵ mol x 454.4 g/mol = 19.9 m g

if 19.9 mg are in 1 L

then 500.0 mg are in - 500.0 mg / 19.9 mg/L = 25.1 L

therefore volume is 25.1 L