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24 August, 18:35

A solution was prepared by mixing 50.00 ml of 0.100 M of HNO3 and 100.00 ml of 0.200 M HNO3. Calculate the molarity of the final solution of nitric acid

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  1. 24 August, 18:51
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    The molarity of this final solution is 0.167 M

    Explanation:

    Step 1: Data given

    Volume of a 0.100 M HNO3 solution = 50.0 mL

    Volume of a 0.200 M HNO3 = 100.0 mL

    Step 2: Calculate moles

    The final molarity must lie between 0.1M and 0.2M

    Moles = molarity * volume

    Moles HNO3 in 50mL of a 0.100M solution = 0.05 L * 0.100 M = 0.005 mol

    Moles HNO3 in 100mL of a 0.200M solution = 0.100 L*0.200 = 0.020mol

    total moles = 0.005+0.020 = 0.025 moles in 150mL solution = 0.150L

    Step 3: Calculate molarity of final solution

    Molarity = mol / volume

    Molarity 0.025 moles / 0.150 L

    Molarity = 0.167M

    The molarity of this final solution is 0.167 M
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