What is the oh-concentration and ph in each solution? (a) 0.225 m koh, (b) 0.0015 m sr (oh) 2?

Q1)

We have been given the OH⁻ concentration, therefore we first need to find the pOH value and then the pH value.

pOH = - log [OH⁻]

pOH = - log (0.225 M)

pOH = 0.65

pH + pOH = 14

pH = 14 - 0.65 = 13.35

Q2)

pOH = - log[OH⁻]

pOH = - log (0.0015 M)

pOH = 2.82

pH + pOH = 14

pH = 14 - 2.82

pH = 11.18