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1 November, 10:35

You will begin by diluting 5.00 mL of a 0.8 M oxalic acid stock solution with water to a final volume of 100.00 mL. What will be the final concentration of the oxalic acid

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  1. 1 November, 10:56
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    0.04M

    Explanation:

    The following were obtained from the question:

    C1 = 0.8M

    V1 = 5mL

    V2 = 100mL

    C2 = ?

    The final concentration of the diluted solution can be obtained by doing the following:

    C1V1 = C2V2

    0.8 x 5 = C2 x 100

    Divide both side by 100

    C2 = (0.8 x 5) / 100

    C2 = 0.04M

    The concentration of the diluted solution is 0.04M
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