How much of 90% ethanol must be mixed with 10% ethanol to make 1 pint of a 40% ethanol solution?

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Chemistry

25 May, 04:44

How much of 90% ethanol must be mixed with 10% ethanol to make 1 pint of a 40% ethanol solution?

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Bridger · Answer 1

Amount of 90% Ethanol=0.375 pint

Amount of 10% Ethanol=0.625 pint

Because:

90x+10y=40

x+y=1

x=1-y

90 (1-y) + 10y=40

90-90y+10y=40

90-80y=40

80y=50

y=5/8

x=1-5/8=3/8