Eva pumps up her bicycle tire until it has a gauge pressure of 413 kilopascals. If the surrounding air is at standard pressure, what is the absolute pressure in the bicycle tire?

The tire pressure is the sum of gauge pressure and the standard pressure of atmospheric pressure

We know that the standard air pressure of surrounding = 101.325 kPa

The given gauge pressure = 413 kPascal

So the tire pressure = 101.325 kPa + 413 = 514.325 K Pa

We can also convert the given pascals to atmosphere or Torr or mmHg or bar

514 kPa

Explanation:

Given that:-

Gauge pressure = 413 kPa

Also, considering atmospheric pressure = 101.325 kPa

The absolute pressure of the tire is equal to the sum of the gauge pressure and atmospheric pressure. So, the expression is:-

Absolute pressure = Gauge pressure + Atmospheric pressure

Applying the values in the above equation as:-

Absolute pressure = 413 kPa + (101.325 kPa = 514.325 kPa ≅ 514 kPa

Thus, absolute pressure in bicycle tire is: - 514 kPa