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4 December, 06:35

Calculate 50g 25.0c to 95.000

O. 897 J / (g. c)

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Answers (1)
  1. 4 December, 07:02
    0
    Q = 3139.5 j

    Explanation:

    Given dа ta:

    Mass = 50 g

    Initial temperature = 25°C

    Final temperature = 95°C

    Specific heat capacity = 0.897 j/g.°C

    Heat absorbed = ?

    Solution:

    Formula:

    Q = m. c. ΔT

    Q = amount of heat absorbed or released

    m = mass of given substance

    c = specific heat capacity of substance

    ΔT = change in temperature

    ΔT = T2 - T1

    ΔT = 95°C - 25°C

    ΔT = 70°C

    Q = m. c. ΔT

    Q = 50 g * 0.897 J/g.°C * 70°C

    Q = 3139.5 j
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