Calculate the work in kilojoules done during a synthesis of ammonia in which the volume contracts from 7.4 l to 4.5 l at a constant external pressure of 44 atm. express your answer using two significant figures.

The work done by the gas can be derived from this formula: Work done = P dV (this is the same as PdeltaV) Now remember P = 44atm and Now dV (deltaV) = 4.5 - 7.4 = - 2.9L (its contracting) = - 2.9 x 10 ^-3m^3 Now remember 1 atm = 101300 pascals Therefore work done by gas = P dV = 44 * - 2.9 * x 10 ^-3 * 101300 Therefore the above result becomes: = - 12925.88 = - 13000J to 2 significant figures