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30 December, 20:05

You need a 20% alcohol solution. on hand, you have a 240 ml of a 15% alcohol mixture. you also have 40% alcohol mixture. how much of the 40% mixture will you need to add to obtain the desired solution?

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  1. 30 December, 20:26
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    0.15*240=36 ml of alcohol in 240 ml of a 15% alcohol mixture

    0.4x = ml of alcohol in x ml of a 40% alcohol mixture

    0.2 (x+240) = ml of alcohol in (x+240) ml of a 20% alcohol mixture

    0.15*240 + 0.4x = 0.2 (x+240)

    36+0.4x=0.2x+48

    0.2x = 12

    x=12/0.2=120/6=20 ml of a 40% alcohol mixture
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