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24 September, 06:32

Formic acid, HCOOH, is a weak electrolyte.

Part A

What solute particles are present in an aqueous solution of this compound?

Express your answer as a chemical formula. If there is more than one answer, enter each answer separated by a comma.

Part B

Write the chemical equation for the ionization of HCOOH.

Express your answer as a balanced chemical equation. Identify all of the phases in your answer.

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Answers (1)
  1. 24 September, 06:59
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    Part A: In an aqueus solution there are three solute particles: H3O+, HCOO - and HCOOH

    Part B: HCOOH (aq) + H2O (l) ⇄ HCOO - (aq) + H3O + (aq)

    Explanation:

    Part A

    Weak acids don't completely ionize in solution, for this reason, a formic acid solution contains un-ionized acid, it means there are many intact molecules of formic acid and only a fraction of the dissolved molecules ionize to form H3O + (aq) and HCOO - (aq).

    Part B

    The chemical equation is:

    HCOOH (aq) + H2O (l) ⇄ HCOO - (aq) + H3O + (aq)

    The double arrows in this equation indicate that the ionization can occur in both the forward and reverse directions.
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