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11 December, 11:48

A 2.50-kg steel gasoline can hold 20.0 L of gasoline when full.

What is the average density of the full gas can, taking into account the volume occupied by steel as well as by gasoline?

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  1. 11 December, 12:01
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    805 kg/m^3.

    Explanation:

    Okay, in the question above we are given the following parameters; the mass of steel gasoline = 2.50-kg, volume of gasoline it can hold = 20.0 L. Then we are asked to calculate the average density of the full can.

    Recall that the formula for Calculating density = mass / volume.

    So, the total mass of the full can = mass of the steel can, m1 + mass of the gasoline, m2.

    Although, we are not given but the density of gasoline = 0.68 g/cm^3 or 6.7 * 10^2 kg/m^3. (Note that you can use any of the value for density of gasoline just take note of the units, for instance one is in g/cm^3 and the other is in kg/m^3). For instance, if we take the one in g/cm^3 we have;

    The mass of gasoline = 0.68 * (10^3 * 20).

    Mass of gasoline = 13.6 * 10^3 g or 13.6 kg.

    Since the mass in the question is given to us In kilograms we will be using the kg unit.

    Therefore, the total mass of the full can = mass of the steel can, m1 + mass of the gasoline, m2.

    ===>2.50 + 13.6.

    Then, going back to the formula for Calculating density, we have;

    Average density = 2.50 + 13.6 / 20 * 10^3.

    Average density = 805 kg/m^3.
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