Identify the neutral element represented by this excited-state electron configuration, then write the ground-state electron configuration for that element.

Excited state: 1s2 2s2 2p3 3s1

The element is oxygen.

1s² 2s² 2p⁴

Explanation:

Let's consider the electron configuration of the excited state.

1s² 2s² 2p³ 3s¹

According to the Aufbau principle, the electron in 3s should occupy the shell with lower energy. The ground-state electron configuration is:

1s² 2s² 2p⁴

The differential electron is in the level 2. Then, the element is in the period 2.

The electrons in the last level are 2 + 4 = 6. Then, the element is in the group VIA or 16.

The element is oxygen.