The ionization constant (Ka) of HF is 6.7 X 10 ^-4. Which of the following is true in a 0.1 M solution of this acid?

Question

Damari

Chemistry

8 December, 23:43

The ionization constant (Ka) of HF is 6.7 X 10 ^-4. Which of the following is true in a 0.1 M solution of this acid?

+2

Answers (1)

Know the Answer?

Natasha · Answer 1

The ionization equation is:

HF ⇄ H (+) + F (-)

The ionization constant is Ka = [H (+) ] * [H (-) ] / [HF]

=> [H (+) ] * [F (-) ] = Ka * [HF]

Given that Ka < 1

[H (+) ] * [F (-) ] < [HF]

Which is [HF] > [H (+) ] * [F (-) ] the option a. fo the list of choices.