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19 November, 06:07

The temperature of a 6.0-g sample of glass changed from 20°C to 45°C when it absorbed 550 J of heat. What is the specific heat of this glass sample?

A. 130 J/g•°C

B. 2300 J/g•°C

C. 0.27 J/g•°C

D. 3.7 J/g•°C

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Answers (2)
  1. 19 November, 06:15
    0
    Answer is: D / 3.7 J/g. C
  2. 19 November, 06:23
    0
    The answer is D

    the formula you need to use is Q=mc (delta) t the delta is usually written as a triangle

    rearrange this to make c the subject as this is the specific heat capacity

    so you get c=Q / (m*tempchange)

    delta t means temp change btw

    plug in you values so 550 / (6*25)

    and you get 3.666666

    to 1 decimal place = 3.7
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