ogen gas and nitrogen gas react to produce ammonia. How many liters of ammonia can be produced from 2 liters of hydrogen gas and 2 liters of nitrogen gas at STP

From 2 liters of hydrogen gas and 2 liters of nitrogen gas, we can produce 1.10 L of ammonia.

Explanation:

First of all, think the ballanced equation:

3H₂ + N₂ → 2NH₃

We must know the density of products and reactants to solve this.

Density shows the relation between mass and volume of a compound, like this:

ρ = mass / volume

ρ H₂ = 0.071 g/L

ρ N₂ = 1.2506 g/L

ρ NH₃ = 0.73 g/L

Let's calculate the mass of reactants

mass of H₂ = ρ H₂. volume H₂

mass of H₂ = 0.071 g/L. 2L → 0.142 g

mass of N₂ = ρ N₂. volume N₂

mass of N₂ = 1.2506 g/L. 2L → 2.50 g

Now, let's calculate the moles

mass H₂ / molar mass H₂ = moles

0.142 g / 2g/m = 0.071 moles

mass N₂ / molar mass N₂ = moles

2.50 g / 28 g/m = 0.089 moles

As the ratio between products is 3:1, it's easy to see that the limiting reactant is H₂. Let's see

1 mol of N₂ needs to react with 3 moles of H₂

0.089 mol of N₂ need to react with (0.089.3) / 1 = 0.267

I only have 0.071 moles.

The ratio between H₂ and NH₃ is 3:2 so the rule of three is:

3 moles of H₂ __ are necessary to make 2 moles of ammonia

0.071 moles of H₂ _ are necessary to make (0.071.2) / 3 = 0.0473 moles

Let's convert this moles in mass, with the molar mass

Moles. Molar mass = mass

0.0473 moles. 17 g/m = 0.804 g

Now, with the density we can know the volume:

ρ NH₃ = 0.73 g/L

Volume NH₃ = mass NH₃ / ρ NH₃

Volume NH₃ = 0.804 g/0.73 g/L

Volume NH₃ = 1.10L