What is the silver concentration in a solution prepared by mixing 250

mL of 0.310 M silver nitrate with 100 mL of 0.160 M of sodium chromate?

0.221M

Explanation:

From the question,

The Molarity of AgNO₂ = 0.310 M

Hence, the concentration of Ag⁺ = 0.301 M

The volume of AgNO₂ = 250 mL

and,

The Molarity of Sodium chromate = 0.160 M

The volume of Sodium chromate = 100 mL.

As the solution is mixed the final volume becomes,

250mL + 100mL = 350mL

Now, using the formula, to find the final molarity of the mixture,

M₁V₁ (initial) = M₂V₂ (final)

substituting the values, in the above equation,

0.310M * 250ml = M₂ * 350ml

M₂ = 0.221M

Hence, the concentration of the silver in the final solution = 0.221M