A 0.500-l sample of gas is at a pressure of 625 mm hg. what must the pressure be (in atm), at constant temperature, if the volume is changed to 925 ml?

Since temperature is held constant; Boyle's law can be expressed as: P 1 * V 1 = P 2 * V 2

Where P1 = 625 and V1 = 0.5 L

V2 = 925 * 10^ (-3) = 0.925 L and P2 = ?

So P2 = (P1 * V1) / P2

P2 = (625 * 0.5) / 0.925

P2 = 337.83 my hg