Hydrogen and iodine gas react to produce hydrogen iodide gas. What is the value of Keq for this reaction if at equilibrium the concentrations of H2, I2, and HI were 0.25 M, 0.035 M, and 0.55 M, respectively?

The answer to your question is Keq = 34.57

Explanation:

Data

[H₂] = 0.25 M

[I₂] = 0.035 M

[HI] = 0.55 M

Balanced chemical reaction

H₂ + I₂ ⇒ 2 HI

Formula

The coefficient of HI will be the exponent.

Keq = [HI]² / [H₂][I₂]

Substitution

Keq = [0.55]² / [0.25][0.035]

Simplification

Keq = 0.3025 / 0.00875

Result

Keq = 34.57