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10 December, 20:59

A certain shade of blue has a frequency of 7.14 * 1014 hz. what is the energy of exactly one photon of this light?

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  1. 10 December, 21:31
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    For this problem, let's use the Planck's equation which is written below:

    E = hv

    where

    E is the energy

    h is Planck's constant equal to 6.626*10⁻³⁴ J·s

    v is frequency

    Solving for E,

    E = (6.626*10⁻³⁴ J·s) (7.14*10¹⁴ s⁻¹)

    E = 4.73*10⁻¹⁹ J
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