If 1.20 moles of copper react with mercuric nitrate how many moles of mercury form

Reaction of Copper with Mercuric Nitrate is as follow,

Cu + Hg (NO₃) ₂ → Cu (NO₃) ₂ + Hg

According to equation,

1 Mole of Cu reacts to form = 1 Mole of Hg

So,

1.20 Moles of Cu will react to produce = X Moles of Hg

Solving for X,

X = (1.20 mol * 1 mol) : 1 mol

X = 1.20 mol of Hg

Result:

1.20 mole of Cu when reacted with mercuric nitrate produces 1.20 moles of Hg.