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7 June, 05:06

Calculate the energy required to heat 322.0g of ethanol from - 2.2°C to 19.6°C. Assume the specific heat capacity of ethanol under these conditions is 2.44·J·g-1K-1. Round your answer to 3 significant digits.

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  1. 7 June, 05:14
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    There is 17.1 kJ energy required

    Explanation:

    Step 1: Data given

    Mass of ethanol = 322.0 grams

    Initial temperature = - 2.2 °C = 273.15 - 2.2 = 270.95K

    Final temperature = 19.6 °C = 273.15 + 19.6 = 292.75 K

    Specific heat capacity = 2.44 J/g*K

    Step 2: Calculate energy

    Q = m*c*ΔT

    ⇒ m = the mass of ethanol = 322 grams

    ⇒ c = the specific heat capacity of ethanol = 2.44 J/g*K

    ⇒ ΔT = T2 - T1 = 292.75 - 270.95 = 21.8 K

    Q = 322 * 2.44 * 21.8 = 17127.8 J = 17.1 kJ

    There is 17.1 kJ energy required
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