A solution is made by dissolving 10.7 g of magnesium sulfate, MgSO4, in enough water to make exactly 100 mL of solution. Calculate the concentration (molarity) of MgSO4 in mmol/L (M).

Question

Lilyana Colon

Chemistry

21 December, 06:27

A solution is made by dissolving 10.7 g of magnesium sulfate, MgSO4, in enough water to make exactly 100 mL of solution. Calculate the concentration (molarity) of MgSO4 in mmol/L (M).

+2

Answers (1)

Know the Answer?

Saniya Flowers · Answer 1

[MgSO₄] = 890 mM/L

Explanation:

In order to determine molarity we need to determine the moles of solute that are in 1L of solution.

Solute: MgSO₄ (10.7 g)

Solvent: water

Solution: 100 mL as volume. (100 mL. 1L / 1000mL) = 0.1L

We convert the solute's mass to moles → 10.7 g / 120.36 g/mol = 0.089 moles

Molarity (mol/L) → 0.089 mol/0.1L = 0.89 M

In order to calculate M to mM/L, we make this conversion:

0.89 mol. 1000 mmoles / 1 mol = 890 mmoles