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15 October, 09:30

Phosphorus-32 has a half-life of 14.0 days. Starting with 4.00 g of 32P, how many grams will remain after 84.0 days?

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  1. 15 October, 09:34
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    T₁=84 d

    t₂=14 d

    m₁=4 g

    n=t₁/t₂

    n=84/14=6

    m₂=m₁/2ⁿ

    m₂=4 / (2⁶) = 0.0625 g

    0.0625 grams will remain after 84.0 days
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