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23 March, 17:48

How many oxygen atoms are contained in 2.74 g of Al2 (SO4) 3?

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Answers (2)
  1. 23 March, 18:13
    0
    either 12 or 24
  2. 23 March, 18:15
    0
    5.79 * 10^23 Oxygen atoms

    Explanation:

    Number of Oxygen atom in the compound = 4*3 = 12

    Molar mass of Al2 (SO4) 3 = 342 g/mol.

    No of mole = mass/molar mass = 2.74/342 = 8.01*10^-03 mole

    2.74g of Al2 (SO4) 3 * 1 mole of Al2 (SO4) 3 / 342g of Al2 (SO4) 3 * 12 mole of Oxygen / 1mole of Al (SO4) 3 * 6.02*10^23 Oxygen atom / 1 mole of Oxygen

    = 5.79*10^23 Oxygen atoms
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