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29 March, 17:00

What is the molarity of the solution resulting from the dissolution of 239 g glucose (C6H12O6) in 250

mL water?

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Answers (1)
  1. 29 March, 17:26
    0
    Molarity = 5.32 M

    Explanation:

    Given dа ta:

    Mass of glucose = 239 g

    Volume = 250 mL (250 / 1000 = 0.25 L)

    Molarity = ?

    Solution;

    Formula:

    Molarity = number of moles / volume in litter

    Number of moles:

    Number of moles = mass / molar mass

    Number of moles = 239 g / 180.2 g/mol

    Number of moles = 1.33 mol

    Molarity:

    Molarity = number of moles / volume in litter

    Molarity = 1.33 mol / 0.25 L

    Molarity = 5.32 M
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