Reducing the volume of a contained gas by one third, while holding temperature constant, causes pressure to Question 1 options:

Reducing the volume of a contained gas by one third, while holding temperature constant, causes pressure to increase by 3.0 times.

Explanation:

Boyle's Law : At constant temperature, the volume of a given quantity of a gas varies inversely with its pressure. It is clear from the data that V ∝ 1/P. Also, PV = constant.

So, for two different values of both P and V:

∴ P₁V₁ = P₂V₂.

∵ V₂ = 1/3V₁

∴ P₂ = P₁V₁/V₂ = P₁V₁ / (1/3V₁) = 3P₁.