How many molecules are in 79g of fe2o3

Question

Madilynn Graves

Chemistry

28 November, 13:41

How many molecules are in 79g of fe2o3

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Answers (1)

Know the Answer?

Alissa Stafford · Answer 1

Convert grams - > mols and then mols - > atoms

We know that there are 6.02 x 10^23 atoms/mol

And we know that there are about 160 grams of fe2o3 per mol

So (79g fe2o3) / (160 g/mol) =.49 mol fe2o3

Now we use avogadro’s number to do

(.49 mol fe2o3) / (6.02 x 10^23 atoms/mol) = the answer.

I’ll leave the easy math to you.