For the reaction? C6H6 + ? O2 →? CO2 + ? H2O 42.5 grams of C6H6 are allowed to react with 113.1 grams of O2. How much CO2 will be produced by this reaction? Answer in units of grams

There will be 143,67g CO2 produced

Explanation:

2 C6H6 + 15 O2 → 12 CO2 + 6 H2O

(42,5 g C6H6) / (78.1124 g C6H6/mol) = 0.54408775 mole C6H6

(113.1 g O2) / (31.9989 g O2/mol) = 3.534496 moles O2

0.54408775 mole of C6H6 would react completely with 0.54408775 x (15/2) = 4.080658 mole O2, but there is more O2 present than that, so O2 is in excess and C6H6 is the limiting reactant.

(0.54408775 mol C6H6) x (12/2) x (44.0096 g/mol) = 143.67 g CO2