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4 January, 08:56

For the reaction? C6H6 + ? O2 →? CO2 + ? H2O 42.5 grams of C6H6 are allowed to react with 113.1 grams of O2. How much CO2 will be produced by this reaction? Answer in units of grams

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  1. 4 January, 09:16
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    There will be 143,67g CO2 produced

    Explanation:

    2 C6H6 + 15 O2 → 12 CO2 + 6 H2O

    (42,5 g C6H6) / (78.1124 g C6H6/mol) = 0.54408775 mole C6H6

    (113.1 g O2) / (31.9989 g O2/mol) = 3.534496 moles O2

    0.54408775 mole of C6H6 would react completely with 0.54408775 x (15/2) = 4.080658 mole O2, but there is more O2 present than that, so O2 is in excess and C6H6 is the limiting reactant.

    (0.54408775 mol C6H6) x (12/2) x (44.0096 g/mol) = 143.67 g CO2
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