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10 January, 01:32

Part complete how much water would you add to 175 ml of 6.00 m hydrochloric acid to prepare a 2.00 m solution of this acid?

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  1. 10 January, 01:54
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    Molarity (M) = moles of solute (mol) / Volume of the solution (L)

    Molarity of the given solution = 6.00 M

    Volume taken to prepare 2.00 M = 175 mL

    moles in 175 mL = 6.00 M x 0.175 L

    = 1.05 mol

    Hence, moles of HCl in 2.00 M solution = 1.05 mol

    By applying formula,

    2.00 M = 1.05 mol / Volume

    Volume = 0.525 L

    Hence, volume needed to prepare the solution = 0.525 L

    Volume of 6.00 M solution + volume of water = 0.525 L

    Hence, the volume of water needed to add = 0.525 L - 0.175 mL

    = 0.350 L = 350 mL
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