You need a 35% alcohol solution. On hand, you have a 280 mL of a 30% alcohol mixture. You also have 75% alcohol mixture. How much of the 75% mixture will you need to add to obtain the desired solution

Question

Sawyer Mcneil

Chemistry

13 August, 16:23

You need a 35% alcohol solution. On hand, you have a 280 mL of a 30% alcohol mixture. You also have 75% alcohol mixture. How much of the 75% mixture will you need to add to obtain the desired solution

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Answers (1)

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Perkins · Answer 1

35 mL

Explanation:

Let the amount of 75% mixture needed be A.

The amount of each solution with their respective concentration to be added together can be expressed as:

0.75A + 0.3 (280) ... eqn 1

The addition of the two solution must merge with the expected concentration and this can be expressed as:

0.35 (A + 280) ... eqn 2

Eqn 1 must be equal to eqn 2, hence:

0.75A + 0.3 (280) = 0.35 (A + 280)

Solve for A.

0.75A + 84 = 0.35A + 98

0.40A = 14

A = 35

Hence, 35 mL of the 75% mixture will be needed.