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11 December, 20:58

A cannonball was launched by a cannon. The function H (t) = -t2+100t+100 describes the position of the cannonball t seconds after it was launched and the height H is in metres. How long did it take for the cannonball to reach its maximum height?

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  1. 11 December, 21:18
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    The answer to your question is t = 50 s

    Explanation:

    Data

    Function

    H (t) = - t² + 100t + 100

    Process

    1. - Find the derivative of the function to get the maximum

    H' (t) = - 2t + 100

    2. - Equal to zero the derivative

    -2t + 100 = 0

    3. - Solve for t

    -2t = - 100

    t = - 100/-2

    t = 50 s

    4. - Conclusion

    It takes 50 s to reach the maximum height
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