Methane and oxygen react to form carbon dioxide and water. what mass of water is formed if 0.80 g of methane reacts with 3.2 g of oxygen to produce 2.2 g of carbon dioxide?

The Balance Chemical Equation is as follow,

CH₄ + 2 O₂ → CO₂ + 2 H₂O

As 1 mole of CH₄ is equal to 16 g, then 0.8 g is equal to 0.05 moles.

Also, if 2 moles of O₂ is equal to 64 g, then 3.2 g is equal to 0.1 moles.

Now, moles of CO₂ and H₂O can also be calculated from equation.

So, reacting 0.05 moles of CO₂ and 0.1 moles of O₂ will produce 0.05 moles (2.2 g) of CO₂ and 0.1 moles (unknown mass) of H₂O)

Calculating for mass of H₂O,

As,

2 moles of H₂O is equal to = 36 g of H₂O

Then

0.1 moles of H₂O will be equal to = X g of H₂O

Solving for X,

X = (0.1 mol * 36 g) : 2 mol

X = 1.8 g of H₂O is produced