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6 July, 23:38

What volume will 2.0 moles of nitrogen occupy at. 947atm and 20° C?

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  1. 6 July, 23:45
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    The volume is 50, 74 l

    Explanation:

    We use the formula PV = nRT. The temperature in Kelvin is = 273 + 20 = 293K

    PV=nRT - --> V = (nRT) / P

    V = (2.0 mol x 0,082 l atm / K mol x 293 K) / 0,947 atm

    V=50,74128828 l
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