What volume will 2.0 moles of nitrogen occupy at. 947atm and 20° C?

The volume is 50, 74 l

Explanation:

We use the formula PV = nRT. The temperature in Kelvin is = 273 + 20 = 293K

PV=nRT - --> V = (nRT) / P

V = (2.0 mol x 0,082 l atm / K mol x 293 K) / 0,947 atm

V=50,74128828 l