A compound is 54.53% C, 9.15% H, and 36.32% O. What is its empirical formula?

The molar mass of the compound is 132 amu. What is its molecular formula?

We are given with a different mass percentages of different elements. we divide first each percentage by the molar mass of each element. Then, divide each by the smallest among them. C has 2, H has 4 adn O has 1. Thus the empirical formula is C2H4O with a molar mass of 44 grams. This is 1/3 od 132 amu. Hence the molecular formula is C6H12O3