Calculate δg o for the reaction between al (s) and cd2 + (aq). enter your answer in scientific notation.

The reaction between Al (s) and Cd²⁺ (aq) is:

Al (s) + Cd²⁺ (aq) → Al³⁺ (aq) + Cd (s)

The half reactions are:

Al³⁺ (aq) + 3 e⁻ → Al (s) E⁰ = - 1.66 V

Cd²⁺ (aq) + 2 e⁻ → Cd (s) E⁰ = - 0.40 V

Reverse the first equation and add to the second one

2 Al (s) + 3 Cd²⁺ (aq) → 2 Al³⁺ (aq) + 3 Cd (s)

So, the overall cell potential is:

E⁰cell = 1.66 - 0.40 = 1.26 V

Free energy of the reaction is:

ΔG⁰ = - n F E⁰cell

= - 6 mol e⁻ * (96485 C / mol e⁻) * (1.26 V)

= - 7.29 x 10⁵ J