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19 July, 23:01

If you have 39.5g of Fe2O3 how many grams of co are requried to complete reaction

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  1. 19 July, 23:26
    0
    20.8g

    Explanation:

    1. Balanced chemical equation

    Fe₂O₃ (s) + 3CO (g) → 2Fe (s) + 3CO₂ (g)

    2. Convert 39.5g of Fe₂O₃ into moles

    #moles = mass in grams / molar mass molar mass of Fe₂O₃ = 159.69 g/mol #moles = 39.5g / 159.69g/mol = 0.24735 mol

    3. Moles of CO

    i) Mole ratio

    3mol CO / 1 mol Fe₂O₃

    ii) Set a proportion

    3 mol CO / 1 mol Fe₂O₃ = x / 0.24735 mol Fe₂O₃

    ⇒ x = 0.24735mol Fe₂O₃ * 3mol CO / 1mol Fe₂O₃ = 0.7426 mol CO

    4. Grams of CO

    molar mass CO: 28.01g/mol mass in grams = #moles * molar mass mass = 0.7426mol * 28.01g/mol = 20.8g ← answer
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