How many grams of beryllium chloride (BeCl2) are needed to make 7.7 L of a 0.69 M solution?

Question

Nash Armstrong

Chemistry

4 December, 06:22

How many grams of beryllium chloride (BeCl2) are needed to make 7.7 L of a 0.69 M solution?

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Answers (1)

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Ryann · Answer 1

419.5 g BeCl2

Explanation:

M = mol solute / L solution

mol solute = M * L solution

mol solute = (0.69 M) * (7.7 L)

mol solute=5.31 mol BeCl2

1 mol BeCl2 - > 79 g

5.31 mol BeCl2 - > x x = 419.5 g BeCl2