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18 May, 08:36

Determine the binding energy per nucleon of an Mg-24 nucleus. The Mg-24 nucleus has a mass of 23.985045. A proton has a mass of 1.00728 amu, a neutron has a mass of 1.008665 amu, and 1 amu is equivalent to 931.5 MeV of energy. Determine the binding energy per nucleon of an Mg-24 nucleus. The Mg-24 nucleus has a mass of 23.985045. A proton has a mass of 1.00728 amu, a neutron has a mass of 1.008665 amu, and 1 amu is equivalent to 931.5 MeV of energy.

a. 8.01 MeV

b. 192 MeV

c. 0.113 MeV

d. 4.41 MeV

e. 0.3050 MeV

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  1. 18 May, 08:52
    0
    192.16MeV

    Explanation:

    Mass of neutron (Mn) = 1.008665 amu

    Mass of proton (Mp) = 1.00728 amu

    Mass of nucleus (Mg-24) = 23.985045 amu

    1 amu = 931.5MeV

    Binding energy of the nucleus is the work or energy needed just to take all the entire nucleons apart so that they are completely separated.

    Mass defect = (mass of proton + mass of neutron) - mass of nucleus.

    Mass defect = [12 (1.00728) + 12 (1.008665) ] - 23.985045

    Mass defect = [ (12.08736 + 12.10398) ] - 23.985045

    Mass defect = 24.19134 - 23.985045

    Mass defect = 0.206295amu

    Binding energy = mass defect * 931.5 MeV

    Binding energy = 0.206295 * 931.5

    Binding energy = 192.16MeV
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