How many grams of solid kcl are needed to prepare 250 ml of 0.235 m solution?

From the question, the molarity of the desired solution was given as 0.235 M while the volume of the solution is 250 mL. Molarity is a unit of concentration used for solutions. It is necessary to first define what molarity is to be able to answer the question. Molarity is defined as number of moles of solute divided by the volume of the solution.

In this case, the amount of solid KCl required to obtain a concentration of 0.235 M in a volume of 250 mL is to be determined. The molar mass of KCl will also be used as conversion factor from unit of moles to grams. The value is 74.5513 g/mol. The following equation is used:

0.235 mol / L x 1 L/1000 mL x 250 mL x 74.5513 g/mol KCl = 4.3799 g KCl

Thus, 4.38 g KCl is required to prepare 250 mL of 0.235 M solution.