At a certain temperature the vapor pressure of pure heptane C7H16 is measured to be 454. mmHg. Suppose a solution is prepared by mixing 102. g of heptane and 135. g of chloroform CHCl3.

Calculate the partial pressure of heptane vapor above this solution. Be sure your answer has the correct number of significant digits.

Question

Suzy

Chemistry

3 March, 08:48

At a certain temperature the vapor pressure of pure heptane C7H16 is measured to be 454. mmHg. Suppose a solution is prepared by mixing 102. g of heptane and 135. g of chloroform CHCl3.

Calculate the partial pressure of heptane vapor above this solution. Be sure your answer has the correct number of significant digits.

+2

Answers (1)

Know the Answer?

Irvin Zuniga · Answer 1

Mass of heptane = 102g

Vapor pressure of heptane = 454mmHg

Molar mass of heptane = 100.21

No of mole of heptane = mass/molar mass = 102/100.21

No of mole of heptane = 1.0179

Therefore the partial pressure of heptane = no of mole heptane * Vapor pressure of heptane

Partial pressure of heptane = 1.0179*454mmHg

Partial pressure of heptane = 462.1096 = 462mmHg

the partial pressure of heptane vapor above this solution = 462mmHg