When the reaction p4o10 + koh → k3po4 + h2o is balanced, how much koh is required to react with 3 moles of p4o10? 1. 9 mol 2. 3 mol 3. 18 mol 4. 36 mol 5. 27 mol?

Question

Nevaeh Clarke

Chemistry

19 November, 13:34

When the reaction p4o10 + koh → k3po4 + h2o is balanced, how much koh is required to react with 3 moles of p4o10? 1. 9 mol 2. 3 mol 3. 18 mol 4. 36 mol 5. 27 mol?

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Answers (1)

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Trenton · Answer 1

The balanced equation for the above reaction is as follows;

P₄O₁₀ + 12KOH - - - > 4K₃PO₄ + 6H₂O

stoichiometry of P₄O₁₀ to KOH is 1:12

1 mol of P₄O₁₀ reacts with 12 mol of KOH

therefore 3 mol of P₄O₁₀ reacts with - 12 x 3 mol of KOH

the number of KOH moles required to react with P₄O₁₀ - 36 mol of KOH

answer is 4. 36 mol