Using fission, what mass m of uranium-235 would be necessary to supply all of the energy that the united states uses in a year, roughly 1.0*1019j

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Beamer

Chemistry

3 May, 08:50

Using fission, what mass m of uranium-235 would be necessary to supply all of the energy that the united states uses in a year, roughly 1.0*1019j

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Nehemiah · Answer 1

The energy released by 1 atom of Uranium is Q=185.*10^6-25.

The energy needed for U. S. that I will name Q2, in eV is: 1*10^19J * (1eV / (1.602*10^-19)) = 6.2422*10^37eV

Q=mc^2

Q2=mc^2

m is the mass of Uranium in kg that we calculated at 3.90*10^-25. We need to fund m2 because that is the unknown mass in the equation for Q2 to give us the energy for the U. S. and remember, Q is the energy that 1 atom of Uranium gives out which is why we took a ratio.

m2=Q2/Q*m=1.3*10^5 kg (final answer)