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8 December, 00:22

Calculate the enthalpy of formation of butane, C4H10, using the balanced chemical

equation and information in Appendix Table B-5 and Table B-14. Write out the solution

according to Hess's law.

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Answers (1)
  1. 8 December, 00:38
    0
    -125.4

    Explanation:

    Target equation is 4C (s) + 5H2 (g) = C4H10

    These are the data equations for enthalpy of combustion

    C (s) + O2 (g) = O2 (g) - 393.5 kJ/mol * 4 H2 (g) + ½O2 (g) = H20 (l) = 285.8 kJ/mol * 5 2CO2 (g) + 3H2O (l) = 13/2O2 (g) + C4H10 - 2877.1 reverse

    To get target equation multiply data equation 1 by 4; multiply equation 2 by 5; and reverse equation 3, so ...

    Calculate 4 (-393.5) + 5 (-285.8) + 2877.6 and you should get the answer.
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