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2 August, 20:41

An unknown gas has a pressure of 699.0 mm Hg at 40.0 C. What is the temperature at standard pressure?

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  1. 2 August, 20:44
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    For this problem the Initial Pressure is P1 = 699.0 mmHg. The Initial Temperature is T1 = 40.0 + 273 = 313K. The Final Pressure is P2 = 760.0 mmHg and the Final Temperature (T2) is what you are asked to solve for.

    Plug into the Gay-Lussac's Law Equation

    P1/T1 = P2/T2

    T2 = 344.75 K
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