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29 November, 00:21

What mass of potassium would react with excess chlorine to produce 156 grams of potassium chloride

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  1. 29 November, 00:33
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    The balanced equation for the above reaction is as follows;

    2K + Cl₂ - - > 2KCl

    stoichiometry of K to KCl is 2:2

    the number of KCl moles produced - 156 g / 74.5 g/mol = 2.09 mol

    we have been given that Cl₂ is in excess. therefore K is the limiting reactant.

    amount of product formed depends on number of limiting reactant present,

    2 mol of K reacts to give 2 mol of KCl

    therefore 2.09 mol of KCl being formed means - 2.09 mol of K has reacted

    mass of K reacted is - 2.09 mol x 39 g/mol = 81.51 g of K

    mass of K reacted is 81.51 g
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