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18 June, 22:11

Hydrogen gas can be prepared by reaction of zinc metal with aqueous HCl:

Zn (s) + 2HCl (aq) → ZnCl₂ (aq) + H2 (g)

How many liters of h₂ would be formed at 742 mm Hg and 15 °C if 25.5 g of zinc was allowed to react?

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  1. 18 June, 22:21
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    The volume of hydrogen gas generated by given reaction is 9.48 L

    Explanation:

    Firstly, we calculate the mole of Zinc added, n = 25.5 / 65 = 0.392 mol

    With the same equivalent, the mole of generated hydrogen gas will be the same, at 0.392 mol.

    Secondly, we get the equation

    P. V = n. R. T

    with P (pressure, atm), V (volume, litre), n (mole, mol), R (ideal gas constant, 0.082), T (temperature, Kelvin)

    So we have to convert the given information to correct unit

    P = 742 mmHg = 0.976 atm

    T = 15 °C = 288 K

    Hence we can calculate the generated volume by

    V = n. R. T / P = 0.392 x 0.082 x 288 / 0.976 = 9.48 L
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