Consider the reaction: 2 SO2 (g) + O2 (g) 2 SO3. If, at equilibrium at a certain temperature, [SO2] = 1.50 M, [O2] = 0.120 M, and [SO3] = 1.25 M, what is the value of the equilibrium constant? none of the above 8.68 6.94 0.14 5.79

5.79

Explanation:

The following data were obtained from the question:

Concentration of SO2, [SO2] = 1.50 M

Concentration of O2, [O2] = 0.120 M

Concentration of SO3, [SO3] = 1.25 M

Equilibrium constant, (K) = ... ?

The balanced equation for the reaction is given below:

2SO2 (g) + O2 (g) 2SO3 (g)

From the balanced equation, the equilibrium constant K is written as follow:

K = [SO3]² / [SO2]²• [O2]

With the above, the value of the equilibrium constant, K can be obtained as follow

K = [SO3]² / [SO2]²• [O2]

K = (1.25) ² / (1.50) ² * 0.120

K = 1.5625 / (2.25 x 0.120)

K = 5.79

Therefore, the equilibrium constant is 5.79.